1. What is the distance between (5,7) and (-2,-2). Round to the nearest tenth, if necessary.
A. 5.7 units
B. 5.8 units
C. 8.6 units<
D. 11.4 units
Help, please!
Not correct... yet
Remember it is the square root of (x2-x1)^2 + (y2 - y1)^2
= square root of (-2 - 5)^2 + (-2 - 7)^2
= square root of (-7)^2 + (-9)^2
= ...
Just use your distance formula, which is just the Pythagorean Theorem in disguise. The distance is
√((-2-5)^2 + (-2-7)^2) = √(7^2 + 9^2) = √(49+81) = √130
so, not C. How did you arrive at that?
The square root of 130 would be 11.4, right?
correct : )
Thank you!
To find the distance between two points in a coordinate plane, you can use the distance formula. The distance formula is derived from the Pythagorean theorem and is given by:
distance = square root of [(x2 - x1)^2 + (y2 - y1)^2]
In this case, the given points are (5, 7) and (-2, -2). Let's label these points as (x1, y1) and (x2, y2) respectively.
Using the formula, we can calculate the distance as follows:
distance = square root of [(-2 - 5)^2 + (-2 - 7)^2]
= square root of [(-7)^2 + (-9)^2]
= square root of [49 + 81]
= square root of 130
To round this answer to the nearest tenth, we look at the digit in the hundredth place, which is 3. Since 3 is less than 5, we round down.
Therefore, the distance between (5, 7) and (-2, -2) is approximately 11.4 units. Hence, the correct option is D.