A sealed container holding 0.0255 L of and ideal gas at 0.983 atm and 65.1 Celsius is placed into a refrigerator and cooled to 39.3 Celsius with no change in the volume. Calculate the final pressure of gas.
Charles' Law
P2/T2=P1/T1
or p2=(39.3+273)*.983atm/(65.1+273)= 92001.9312 pascals or about .92 atm