Question 9. Determine the number a so that the line ax-5y + 3 = 0 passes through the point (2, -3).
Would it be correct to toss this into a formula and solve for A?
I.e. a*2-5*-3+3=0
a*2+15+3=0
a*2+18=0
a*2=-18
a=-9
?
Correct : )
PS... GREAT mathematical form.
One equal sign per line.
Good structure : )
Awesome thanks!
Yes, your approach is correct. To determine the value of 'a' so that the line passes through the point (2, -3), you can substitute the coordinates of the point into the equation of the line and solve for 'a'.
The equation of the line is given as ax - 5y + 3 = 0. By substituting the values x = 2 and y = -3 into the equation, you get:
a*2 - 5*(-3) + 3 = 0
Now, simplify the equation:
2a + 15 + 3 = 0
Combine like terms:
2a + 18 = 0
To solve for 'a', isolate it on one side of the equation:
2a = -18
Finally, divide both sides of the equation by 2:
a = -9
So, the value of 'a' that makes the line ax - 5y + 3 = 0 pass through the point (2, -3) is -9.