One of the numbers increased by 10. How did the average of the two numbers change?
Pls tell me the answer thats all i neeed
e.g. suppose your two numbers were 20 and 60
then their average is 40
now add 10 to one of them, what is your new number?
try it with 2 other numbers of your own
To answer the question, we need to understand how the average is calculated and how it changes when one of the numbers is increased.
The average of two numbers is obtained by adding the two numbers together and dividing the sum by 2.
Let's suppose the two original numbers are A and B. The average is calculated as (A + B) / 2.
If one of the numbers, let's say A, is increased by 10, the new value of A becomes A + 10. The other number B remains the same.
The new average, let's call it Avg', is calculated as (A' + B) / 2, where A' is the increased value of A.
Substituting the new values, we get (A + 10 + B) / 2.
Simplifying further, we have (A + B + 10) / 2.
Comparing this with the original average (A + B) / 2, we can see that the new average Avg' is greater than the original average by a constant value of 10/2, which is 5.
Therefore, when one of the numbers is increased by 10, the average of the two numbers increases by 5.
current average: (x+y)/2
so, suppose y increases by 10. Then
new average: (x+ y+10)/2 = (x+y)/2 + 10/2
so, what do you think?
yes, please think, do not just ask for answers.