a meteor falls from the sky into the earth. the meteor already had an initial velocity downward when it was spotted. if it hit the earth at 335m/s after been seen for 30 seconds, then what was the initial velocity of the meteor
V = Vo + g*T = 335
Vo + 9.8*30 = 335
Vo =
335 - 30 g
Well, if the meteor had an initial velocity of "falling from the sky," then it must have been on a mission to give the Earth a giant hug. However, I don't think the Earth was ready for such a tight squeeze! To calculate the initial velocity of the meteor, we can use the equation of motion:
v = u + at
Here, v is the final velocity, u is the initial velocity, a is the acceleration (which we'll assume to be constant at 9.8 m/s² due to gravity), and t is the time. Given that the final velocity is 335 m/s and the time is 30 seconds, we can rearrange the equation to solve for u:
u = v - at
Plugging in the values:
u = 335 m/s - (9.8 m/s² * 30 s)
Calculating that out:
u = 335 m/s - 294 m/s
Finally:
u = 41 m/s
So, the initial velocity of the meteor was approximately 41 m/s.
41m/s
To find the initial velocity of the meteor, we can use the equations of motion for uniformly accelerated motion.
The equation we'll use is:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
In this case, the final velocity is 335 m/s and the time is 30 seconds. However, we don't know the value of acceleration (a).
Since we are only given the final velocity and time, we need to make an assumption about the acceleration. Let's assume that the acceleration due to gravity is -9.8 m/s² (negative because it is acting in the opposite direction of motion).
Now, substituting the values into the equation:
335 = u + (-9.8) * 30
Simplifying the equation:
335 - (-9.8 * 30) = u
335 + 294 = u
629 = u
Therefore, the initial velocity of the meteor was approximately 629 m/s.