The perimeter of the room is 50m. the length exceeds by the width by 3.3m. Find the length of the room.
2(w + w+3.3) = 50
find w, the width, and then the length is w+3.3
Find l and w, when the perimeter is 50m and the width exceeds the length by 3.3
w=x
l=x+3.3
2(x+x+3.3)=50
2x+2x+6.6=50
4x+6.6=50 (minus 6.6 on both sides)
4x=43.4 (devide 4 on both sides)
x=10.85
w=x
w=10.85m
l=x+3.3
l=10.85+3.3
l=14.15m
Therefore, the width is 10.85m and the length is 14.15m
To find the length of the room, we can set up a system of linear equations based on the given information.
Let's denote the length of the room as L and the width of the room as W.
According to the problem, the perimeter of the room is 50m. The formula for the perimeter of a rectangle is given by:
Perimeter = 2 * (Length + Width)
Therefore, we have the equation:
2 * (L + W) = 50
We are also given that the length exceeds the width by 3.3m. This can be represented as:
L = W + 3.3
Now we can substitute the value of L from the second equation into the first equation:
2 * (W + 3.3 + W) = 50
Simplifying the equation:
2 * (2W + 3.3) = 50
4W + 6.6 = 50
4W = 50 - 6.6
4W = 43.4
W = 43.4 / 4
W = 10.85
Now that we have found the value of W, we can substitute it back into the equation L = W + 3.3 to find the length L:
L = 10.85 + 3.3
L = 14.15
Therefore, the length of the room is 14.15 meters.