how do you expand double brackets?
give an example, or try google first.
to expand double brackets you use FOIL
for example
(a+4)(a+2)
for this one you get A from the first set of bracket and multiply (a+2) which becomes: a^2+2a
then you get 4 from the first set of brackets and multiply (a+2) which becomes: 4a +8 (4*2=8)
and you put a^2+2a and 4a +8 together and becomes a^2+2a+4a+8 and add 2a+4a which becomes 6a
so the final answer is a^2+6a+8
(a+4)(a+2)
=a^2+2a+4a+8
=a^2+6a+8
(a+4)(a+2)
when in danger or in doubt:
(a+4)(a+2)
is the same as
a (a+2) + 4(a+2)
= a^2 + 2 a + 4 a + 8
= a^2 + 6 a + 8
You do not really need that for a FOIL problem, but keep it in mind for when things get messier.
for distributive property see:
https://www.mathsisfun.com/definitions/distributive-law.html
To expand double brackets, you need to apply the distributive property, which states that for any real numbers (or algebraic expressions) a, b, and c, the expression a(b + c) can be expanded as ab + ac. Here's an explanation of the steps involved:
1. Start with a pair of double brackets, for example, (x + 1)(2x - 3).
2. Multiply the first terms of each bracket: x * 2x = 2x^2.
3. Multiply the outer terms of each bracket: x * (-3) = -3x.
4. Multiply the inner terms of each bracket: 1 * 2x = 2x.
5. Multiply the last terms of each bracket: 1 * (-3) = -3.
6. Simplify the resulting terms: 2x^2 - 3x + 2x - 3.
7. Combine like terms by adding or subtracting coefficients: 2x^2 - x - 3.
Now you have expanded the double brackets (x + 1)(2x - 3), and the expanded form is 2x^2 - x - 3.