For an experiment, you place 15 g of ice with a temperature of -10 degrees C into a cup and label it A. You also add place 25 g of ice at the same temperature into another cup and label it B. Which of the following statements is true?
The average kinetic energy of the ice in A cup is...
A) less than that in cup B
B) greater than that in cup B
C) equal to that in cup B
D) They are not comparable
Oh and my answer is D not comparable
To determine the average kinetic energy of the ice in cups A and B, we need to consider the formula for kinetic energy and the factors that affect it.
The kinetic energy (KE) of an object is given by the equation KE = 1/2 * mv^2, where m is the mass of the object and v is its velocity.
In this case, the ice in both cups has the same mass (15 g in cup A and 25 g in cup B), but we don't have any information about their velocities. However, we know that both cups contain ice at the same temperature (-10 degrees C).
At the same temperature, the average kinetic energy of the ice particles in a sample can be considered proportional to the average velocity of the particles. The average velocity of the particles depends on the temperature.
Lower temperatures generally correspond to lower average velocities and therefore lower average kinetic energies. Conversely, higher temperatures lead to higher average velocities and higher average kinetic energies.
Since both cups contain ice at the same temperature, -10 degrees C, the average kinetic energy of ice in cup A will be the same as the average kinetic energy of ice in cup B. Therefore, the answer is:
C) equal to that in cup B.