2Ca(s)+O2(g) → 2CaO(s)
ΔH∘rxn= -1269.8 kJ ΔS∘rxn= -364.6 J/K
Calculate the free energy change for the reaction at 22 ∘C
dGrxn = dHrxn - TdSrxn
Substitute and calculate. Post your work if you get stuck.
To calculate the free energy change (ΔG) for a reaction using the given conditions, you can use the equation:
ΔG = ΔH - TΔS
where:
ΔG is the free energy change
ΔH is the enthalpy change
ΔS is the entropy change
T is the temperature in Kelvin (K)
Given:
ΔH∘rxn = -1269.8 kJ
ΔS∘rxn = -364.6 J/K
T = 22 ∘C
First, convert the temperature from Celsius to Kelvin:
T = 22 + 273 = 295 K
Next, convert the enthalpy change from kilojoules (kJ) to joules (J):
ΔH∘rxn = -1269.8 kJ = -1269.8 × 1000 J = -1,269,800 J
Now, we can substitute the values into the equation to calculate the free energy change:
ΔG = ΔH - TΔS
ΔG = -1,269,800 J - (295 K) * (-364.6 J/K)
ΔG = -1,269,800 J + 107,342 J
ΔG = -1,162,458 J
The free energy change for the reaction at 22 ∘C is -1,162,458 J.