Find the normal approximation of P(X=12) when mean=9.5 and variance=5.89.
well using
http://davidmlane.com/hyperstat/z_table.html
mean = 9.5 and SD = sqrt (5.89) = 2.43
p of between 11.5 and 12.5 is 0.0967
http://davidmlane.com/hyperstat/z_table.html
mean = 9.5 and SD = sqrt (5.89) = 2.43
p of between 11.5 and 12.5 is 0.0967