the deer is standing still while it is struck by the car. The deer has a mass of 195 kg and the car has a mass of 1280 kg. What is the impulse experienced by the car during the collision.
What is speed of car?
the speed is 12.51 m/s during collision and 33.97 m/s when the deer crossed the road at the start
Impulse = change in momentum = MV1-MV2 = 1280*33.97-(1280*12.51) =
To calculate the impulse experienced by the car during the collision, we need to use the equation:
Impulse = Change in momentum
The momentum of an object is given by the equation:
Momentum = Mass × Velocity
Since the deer is standing still, its initial velocity (u) is 0 m/s. The car's initial velocity is also not given, but we can assume it is moving with a certain velocity (let's call it v) before the collision.
After the collision, both the car and the deer move together with the same final velocity (let's call it vf). Since the deer is struck by the car, it will start moving in the same direction as the car.
Now, the change in momentum (Δp) for the car can be calculated as:
Δp = m × Δv
= m × (vf - u)
Given:
Mass of the deer (m1) = 195 kg
Mass of the car (m2) = 1280 kg
Initial velocity of the car (u) = v (unknown)
Final velocity of the car and deer (vf) = v (unknown)
Since the deer is standing still, its initial momentum (p1) is zero.
So, the initial momentum (p2i) of the car can be calculated by:
p2i = m2 × u
After the collision, both the car and the deer move with the same velocity, so the final momentum (p2f) can be calculated as:
p2f = (m1 + m2) × vf
Therefore, the change in momentum (Δp) can be written as:
Δp = p2f - p2i
= (m1 + m2) × vf - (m2 × u)
Since we now have the formula to calculate impulse, let's substitute the given values and solve for the impulse experienced by the car during the collision.