A gas has a volume of 590 mL at a temperature of -55.0°C. What volume will the gas occupy at 30.0°C? Show your work.
Someone please help!! I don’t know how to do this.
To solve this problem, we can use the combined gas law, which relates the initial and final conditions of temperature, pressure, and volume of a gas. The formula for the combined gas law is:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures,
V1 and V2 are the initial and final volumes,
T1 and T2 are the initial and final temperatures.
In this problem, we are given:
V1 = 590 mL (initial volume)
T1 = -55.0°C (initial temperature)
T2 = 30.0°C (final temperature)
We need to find V2 (final volume). We can rearrange the equation to solve for V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
However, the problem does not provide information about the pressure of the gas. To solve this problem completely, we would need the pressure.
Or you can use the formula which is
(V1/T1) = (V2/T2)
Remember T must be in kelvin.
the volume is directly proportional to the ABSOLUTE (Kelvin) temperature
convert the Celsius temps to Kelvin
use the proportion to find the new volume