What volume (in ml) of 0.170 M sodium thiosulphate, Na2S2O3, solution is needed to prepare 250.0 mL of 0.0120 M sodium thiosulphate solution?
See the post by leo directly above. Post your work if you get stuck.
To find the volume of the 0.170 M sodium thiosulphate solution needed, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the initial solution in M (0.170 M)
V1 = volume of the initial solution in mL (what we're trying to find)
C2 = concentration of the final solution in M (0.0120 M)
V2 = volume of the final solution in mL (250.0 mL)
Rearranging the formula to solve for V1, we have:
V1 = (C2 * V2) / C1
Substituting the given values, we have:
V1 = (0.0120 M * 250.0 mL) / 0.170 M
V1 = 1.7647 mL
Therefore, you will need approximately 1.7647 mL of the 0.170 M sodium thiosulphate solution to prepare 250.0 mL of the 0.0120 M sodium thiosulphate solution.