Find the measure of the exterior angles of the following regular polygons: a triangle, a quadrilateral, a pentagon, an octagon, a decagon, a 30-gon, a 50-gon, and a 100-gon.
thats bullyism
To find the measure of the exterior angles of a regular polygon, we can use the formula:
Exterior angle = 360 degrees / number of sides
a) Triangle:
A triangle has 3 sides, so the exterior angle is:
Exterior angle = 360 degrees / 3 sides = 120 degrees
b) Quadrilateral:
A quadrilateral has 4 sides, so the exterior angle is:
Exterior angle = 360 degrees / 4 sides = 90 degrees
c) Pentagon:
A pentagon has 5 sides, so the exterior angle is:
Exterior angle = 360 degrees / 5 sides = 72 degrees
d) Octagon:
An octagon has 8 sides, so the exterior angle is:
Exterior angle = 360 degrees / 8 sides = 45 degrees
e) Decagon:
A decagon has 10 sides, so the exterior angle is:
Exterior angle = 360 degrees / 10 sides = 36 degrees
f) 30-gon:
A 30-gon has 30 sides, so the exterior angle is:
Exterior angle = 360 degrees / 30 sides = 12 degrees
g) 50-gon:
A 50-gon has 50 sides, so the exterior angle is:
Exterior angle = 360 degrees / 50 sides = 7.2 degrees
h) 100-gon:
A 100-gon has 100 sides, so the exterior angle is:
Exterior angle = 360 degrees / 100 sides = 3.6 degrees
the sum of the exterior angles of ANY regular polygon is 360 degrees
I will do the octagon, you do the rest.
exterior angle = 360/8 degrees = 45 degrees