For the inequality
x+1≥4, which solution set satisfies the inequality?
A.
{0, 1, 2}
B.
{0, 2, 4}
C.
{3, 4}
D.
{2, 4}
no, Keyshawn Johnson is not correct
The answer is {2,4}
Is Keyshawn Johnson correct?
It’s 3,4 one trust me the other 2 are wrong
Im just tryna get answer for my homework and you are all getting different answers LMAOO
{0, 2, 4}
3,4
To find out which solution set satisfies the inequality x + 1 ≥ 4, we can substitute the values in each set one by one and check if the inequality holds true.
Let's start with option A: {0, 1, 2}.
For x = 0: 0 + 1 ≥ 4 → 1 ≥ 4 (not true)
For x = 1: 1 + 1 ≥ 4 → 2 ≥ 4 (not true)
For x = 2: 2 + 1 ≥ 4 → 3 ≥ 4 (not true)
Now let's move on to option B: {0, 2, 4}.
For x = 0: 0 + 1 ≥ 4 → 1 ≥ 4 (not true)
For x = 2: 2 + 1 ≥ 4 → 3 ≥ 4 (not true)
For x = 4: 4 + 1 ≥ 4 → 5 ≥ 4 (true)
Option B has one value, x = 4, that satisfies the inequality.
Next, let's consider option C: {3, 4}.
For x = 3: 3 + 1 ≥ 4 → 4 ≥ 4 (true)
For x = 4: 4 + 1 ≥ 4 → 5 ≥ 4 (true)
Option C has two values, x = 3 and x = 4, that satisfy the inequality.
Finally, let's look at option D: {2, 4}.
For x = 2: 2 + 1 ≥ 4 → 3 ≥ 4 (not true)
For x = 4: 4 + 1 ≥ 4 → 5 ≥ 4 (true)
Option D has one value, x = 4, that satisfies the inequality.
Therefore, the solution set that satisfies the inequality x + 1 ≥ 4 is option C: {3, 4}.