Study the following diagram, where point C lies in the exterior of circle O.
Segment WC is tangent to circle O at point W.
CO¯¯¯¯¯¯¯¯, CW¯¯¯¯¯¯¯¯¯, and OW¯¯¯¯¯¯¯¯¯ are drawn in to create △OWC.
If WC=15 and CO=17, what is OW?
Enter the correct value.
could somebody help please i need help
Use the equation A^2+B^2=C^2, C being the hypotenuse/ line CO. You get 9^2+12^2=x^2 and the answer is 15, just took the test and it is right.
the answer to this one is 8
To find the value of OW in triangle OWC, we can use the Pythagorean theorem. In a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
In this case, OW is the hypotenuse of triangle OWC, and WC and CO are the other two sides. We know that WC = 15 and CO = 17.
Using the Pythagorean theorem, we can write the equation:
OW^2 = WC^2 + CO^2
Substituting in the given values:
OW^2 = 15^2 + 17^2
Simplifying:
OW^2 = 225 + 289
OW^2 = 514
To find OW, we take the square root of both sides:
OW = √514
Using a calculator, we find that OW is approximately 22.68.
Therefore, the value of OW is approximately 22.68.