Calculate the electric field intensity of a point 15CM from a charge of 10NC.
E=k q/r^2
4*10^6 N/c
To calculate the electric field intensity of a point due to a charge, you can use Coulomb's law. Coulomb's law states that the electric field intensity (E) created by a point charge is directly proportional to the magnitude of the charge (Q) and inversely proportional to the square of the distance (r) between the point charge and the point at which you want to calculate the electric field intensity. Mathematically, it can be expressed as:
E = k * (Q / r^2)
Where:
E is the electric field intensity,
k is the electrostatic constant (k = 9 x 10^9 Nm^2/C^2),
Q is the charge, and
r is the distance.
Plugging in the given values:
E = (9 x 10^9 Nm^2/C^2) * (10 NC / (0.15 m)^2)
Converting cm to m, we have:
E = (9 x 10^9 Nm^2/C^2) * (10 NC / (0.15 m)^2)
Calculating the equation:
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-9 C / (0.15 m)^2)
E = (9 x 10^9 Nm^2/C^2) * (10 x 10^-9 C / (0.0225 m^2))
E = (9 x 10^9 Nm^2/C^2) * (1 x 10^-8 C / 0.0225 m^2)
E = 400 N/C
Therefore, the electric field intensity at a point 15 cm away from a charge of 10 nC is 400 N/C.
To calculate the electric field intensity at a point due to a charge, you can use Coulomb's Law. Coulomb's Law states that the electric field intensity (E) at a point is directly proportional to the charge (q) and inversely proportional to the square of the distance (r) between the point and the charge. Mathematically, it can be written as:
E = (k * q) / r^2
where E is the electric field intensity, q is the charge, r is the distance between the charge and the point, and k is the electrostatic constant, approximately equal to 9 x 10^9 Nm^2/C^2.
In this case, the charge is 10 NC (Coulombs) and the distance is 15 cm. However, it's important to note that the electric field intensity should be calculated with the distance measured in meters, not centimeters. Therefore, we need to convert 15 cm to meters.
1 cm = 0.01 meters
So, 15 cm = 15 x 0.01 = 0.15 meters.
Now we can substitute the values into the formula:
E = (9 x 10^9 Nm^2/C^2 * 10 NC) / (0.15 m)^2
Simplifying further:
E = (9 x 10^9 N * m^2 * C / C) / (0.0225 m^2)
E = 9 x 10^9 N / 0.0225 m^2
E = 4 x 10^11 N/C
Therefore, the electric field intensity at a point 15 cm from a charge of 10 NC is approximately 4 x 10^11 N/C.