Calculate the linear expansivity of brass of length 120m, that assumes a new length of120.05m when heated through a temperature 100c
A brass measuring tape is correct at 20 degree Celsius. The volume obtained when the length of a field is measured with the rule at 50 degree Celsius appears to be 70.5m. The exact question is: Benzyl alcohol (bp 205 degree C) was selected by a student to crystallize fluorenol (mp 153-154 degrees C) because the solubility characteristics of this solvent are appropriate. However, this solvent is not a good choice.
To calculate the linear expansivity of brass, we can use the formula:
ΔL = α * L * ΔT,
where:
ΔL is the change in length,
α is the linear expansivity,
L is the original length, and
ΔT is the change in temperature.
Given:
L = 120 m (original length)
ΔL = 120.05 m - 120 m = 0.05 m (change in length)
ΔT = 100 °C (change in temperature)
We can rearrange the formula to solve for α:
α = ΔL / (L * ΔT)
Now we can substitute the given values:
α = 0.05 m / (120 m * 100 °C)
Simplifying further:
α = 0.05 / (120 * 100)
α = 4.1667 × 10^(-6) per °C
Therefore, the linear expansivity of brass is approximately 4.1667 × 10^(-6) per °C.