A body of weight 80N stands in an elevator that is about to move,the force exalted on the floor in the body as the elevator move's upwards with acceleration of 5m is?
The elevator move's upwards at a constant speed
To find the force exerted on the floor of the elevator when it moves upwards with an acceleration of 5 m/s², you need to consider the net force acting on the body.
In this case, there are two forces acting on the body: its weight (mg) and the force exerted by the floor of the elevator (F_floor).
Net force (F_net) = ma, where m is the mass of the body and a is the acceleration.
Since the weight of the body is given as 80 N, you can divide it by the acceleration due to gravity (approximately 9.8 m/s²) to find the mass (m):
m = 80 N / 9.8 m/s² ≈ 8.2 kg
Now, calculate the net force:
F_net = m * a = 8.2 kg * 5 m/s² = 41 N
Since the net force is equal to the sum of the weight (mg) and the force exerted by the floor (F_floor), you can rearrange the equation:
F_floor = F_net - mg
F_floor = 41 N - (8.2 kg * 9.8 m/s²) = 41 N - 80.36 N ≈ -39 N
Therefore, the force exerted on the floor of the elevator is approximately -39 N (negative because it is directed opposite to the motion).
the acceleration force of the elevator is added to the gravitational force
... f = m a = (80 / g) * (g + 5)
when the elevator's speed is constant, the force is just the weight ... 80 N