the sum of a number times 2 and 17 is at least -25
a number times 2 ... 2x
sum of ... + 17
is at least ... ≥
so put it all together
2x + 17 => -25.
To find the number that satisfies the given condition, we can create an equation. Let's represent the unknown number as "x".
According to the question, the sum of the number times 2 and 17 is at least -25. Mathematically, this can be written as:
2x + 17 ≥ -25
To isolate the variable, we can subtract 17 from both sides of the inequality:
2x + 17 - 17 ≥ -25 - 17
2x ≥ -42
Finally, we divide both sides by 2 to solve for "x":
x ≥ -42/2
x ≥ -21
Therefore, any number greater than or equal to -21 would satisfy the given condition.
To solve this problem, let's break it down into steps:
Step 1: Begin by setting up an equation with the information given. Let's call the unknown number 'x'.
- The sum of 'x' times 2 and 17 can be expressed as (2x + 17).
Step 2: Translate the given condition into an inequality.
- The phrase "at least" implies that the sum is greater than or equal to -25. So we can write it as:
(2x + 17) ≥ -25
Step 3: Solve the inequality for 'x'.
- To isolate 'x', we need to subtract 17 from both sides of the inequality:
2x + 17 - 17 ≥ -25 - 17
2x ≥ -42
- Next, we divide both sides of the inequality by 2 to solve for 'x':
(2x / 2) ≥ (-42 / 2)
x ≥ -21
Step 4: Interpret the solution.
- The value of 'x' is at least -21 in order for the sum of 'x' times 2 and 17 to be greater than or equal to -25.
Therefore, any number greater than or equal to -21 satisfies the condition.