Center & Radius of circle?
(x+1)^2+(y+7)^2=36
the radius is the square root of the number after the equal sign: 36. the square root of 36 is 6
so the radius is 6
if you wanna find the center you find what makes each of the squared parts zero:
(x+1)^2=0 & (y+7)^2 --> x=-1, y=-7 --> center: (-1,-7)
Sierra/Pietra/BLEH/Layla/whoever else ~ Please pick one name and keep it. Playing name games and answering yourself is childish.
To identify the center and radius of a circle, we need to express the equation of the circle in standard form, which is as follows:
(x - h)^2 + (y - k)^2 = r^2
In the given equation, (x+1)^2 + (y+7)^2 = 36, we can observe that the terms (x+1)^2 and (y+7)^2 are already in a format close to the standard form. To rewrite this equation in standard form, we need to expand the squared terms:
(x+1)^2 + (y+7)^2 = 36
x^2 + 2x + 1 + y^2 + 14y + 49 = 36
Rearranging the terms, we have:
x^2 + y^2 + 2x + 14y + (1 + 49 - 36) = 0
x^2 + y^2 + 2x + 14y + 14 = 0
Comparing this equation with the standard form (x - h)^2 + (y - k)^2 = r^2, we can identify the center and radius:
Center = (-h, -k) = (-1, -7)
Radius = sqrt(r^2) = sqrt(36) = 6
Therefore, the center of the circle is (-1, -7) and the radius is 6.