C2H2 + 3O2 ---------> 2H2O + 2CO2
What is the volume of Oxygen required for the complete combination of 12.5cm^3 of ethene.
You don't have a balanced equation. Here is a correct one.
2C2H2 + 5O2 ---------> 2H2O + 4CO2
Here is a short cut you can use when gases are involved; i.e., use volumes as if they were mols.
12.5 cc C2H2 x (5 mols O2/4 mols C2H2) = ? cc O2 required.
To determine the volume of oxygen required for the complete combination of 12.5 cm^3 of ethene (C2H2), we need to use the stoichiometry of the balanced chemical equation.
The balanced equation provided is:
C2H2 + 3O2 → 2H2O + 2CO2
From the equation, we can see that the ratio of oxygen to ethene is 3:1. This means that for every 1 volume of ethene, we need 3 volumes of oxygen.
Given that we have 12.5 cm^3 of ethene, we can calculate the volume of oxygen required as follows:
Volume of oxygen = (Volume of ethene) x (Volume ratio of oxygen to ethene)
Volume of oxygen = 12.5 cm^3 x 3
Volume of oxygen = 37.5 cm^3
Therefore, the volume of oxygen required for the complete combination of 12.5 cm^3 of ethene is 37.5 cm^3.