How much tension must a rope withstand if it is used to accelerate a 960-kg car horizontally along a frictionless surface at 1.20 m/s^2?
F = m a = 960 * 1.20 Newtons
The vertical forces (weight and force up from floor) are irrelevant because orthogonal (perpendicular) to your problem.
To find the tension in the rope, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this case, the net force acting on the car is the tension in the rope. Let's denote the tension as "T". The mass of the car is 960 kg, and the acceleration is 1.20 m/s².
The formula we'll use is:
Net force = Mass × Acceleration
T = m × a
T = 960 kg × 1.20 m/s²
T = 1152 N
Therefore, the tension in the rope must withstand 1152 Newtons of force in order to accelerate the 960-kg car horizontally along a frictionless surface at 1.20 m/s².
To calculate the tension in the rope, we can use Newton's second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration.
The force applied by the rope is equal to the tension in the rope, and the force required to accelerate the car can be calculated using the following formula:
Force = mass × acceleration
Plugging in the given values:
Force = 960 kg × 1.20 m/s^2
Force = 1152 N
Therefore, the tension in the rope must withstand 1152 Newtons of force.