19x^-2
why is this not a monomial?
thank you
negative exponent is not allowed in monomial
see:
http://www.icoachmath.com/math_dictionary/Monomial.html
In multiplying polynomial with monomial no need to change the exponents of variables
To determine whether an expression is a monomial, we need to understand the definition of a monomial. A monomial is a polynomial with only one term. In this case, the expression 19x^(-2) is not a monomial because it contains two terms. We have the term "19" and the term "x^(-2)".
To understand this, let's break down the individual terms in the expression:
- The term "19" is a constant term since it does not have any variables.
- The term "x^(-2)" contains a variable, "x", raised to a negative exponent, "-2". This term represents the reciprocal of x squared and has an exponent.
Since the given expression consists of both a constant term and a term with a variable raised to an exponent, it does not meet the criteria for a monomial, and thus, it is not a monomial.