Calculate the mass of potassium hydrogen tartrate that is measured to prepare 100 mL of a 0.150 mol/L standard solution
How many moles do you need? That's M x L = ?
Then moles = grams/molar mass. You know molar mass and you know moles, solve for grams KHtartrate
100 mL = 0.1 L
To determine amount of potassium hydrogen tartrate needed in moles:
n KC4H5O6 = (0.1 L) x (0.150 mol/ 1 L) = 0.015 moles
Convert this amount into mass of potassium hydrogen tartrate by using its molar mass, M. The molar mass of potassium hydrogen tartrate is 188.177 g/mol.
m KC4H5O6 = (0.015 moles) x (188.177 g/ 1 mol) = 2.822655 grams
You could combine the two above steps:
m KC4H5O6 = (0.1 L) x (0.150 mol/ 1 L) x (188.177 g/ 1 mol) = 2.822655 grams
To calculate the mass of potassium hydrogen tartrate needed to prepare a 0.150 mol/L standard solution with a final volume of 100 mL, you can follow these steps:
Step 1: Convert the concentration to moles per liter.
0.150 mol/L = 0.150 moles/1 L
Step 2: Determine the number of moles in the desired volume.
moles = concentration × volume
moles = 0.150 moles/L × 0.100 L (since 100 mL is equivalent to 0.100 L)
Step 3: Calculate the molar mass of potassium hydrogen tartrate.
The molar mass of potassium hydrogen tartrate (KHC4H4O6) is:
K: 39.10 g/mol
H: 1.01 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
Adding these together gives: 39.10 + 1.01*(4) + 12.01*(4) + 16.00*(6) = 226.22 g/mol
Step 4: Calculate the mass of potassium hydrogen tartrate.
mass = moles × molar mass
mass = 0.150 moles × 226.22 g/mol
The mass of potassium hydrogen tartrate needed to prepare a 0.150 mol/L standard solution with a final volume of 100 mL is approximately 33.93 grams.
To calculate the mass of potassium hydrogen tartrate (KHC4H4O6) needed to prepare a 0.150 mol/L standard solution, we will use the equation:
Mass (g) = Molar concentration (mol/L) × Volume (L) × Molar mass (g/mol)
Step 1: Find the molar mass of potassium hydrogen tartrate (KHC4H4O6).
The molar mass can be calculated by adding up the atomic masses of all the individual atoms.
K: 1 atom × atomic mass of potassium (39.10 g/mol)
H: 5 atoms × atomic mass of hydrogen (1.01 g/mol)
C: 4 atoms × atomic mass of carbon (12.01 g/mol)
O: 6 atoms × atomic mass of oxygen (16.00 g/mol)
Molar mass = (1 × 39.10) + (5 × 1.01) + (4 × 12.01) + (6 × 16.00) = 204.23 g/mol
Step 2: Calculate the mass of potassium hydrogen tartrate.
We are given:
Molar concentration = 0.150 mol/L
Volume = 100 mL = 0.100 L (convert mL to L)
Mass (g) = 0.150 mol/L × 0.100 L × 204.23 g/mol
Mass (g) = 3.063 g
Therefore, the mass of potassium hydrogen tartrate required to prepare 100 mL of a 0.150 mol/L standard solution is 3.063 grams.