Study the balanced equation.
C + O2 → CO2
(M O2 = 32 g/mol; M CO2 = 44 g/mol)
When 78.0 g of carbon dioxide (CO2) are produced, what mass of oxygen is present in the product?
56.7 g oxygen
35.0 g oxygen
52.3 g oxygen
28.4 g oxygen
I do not believe it is 52.3 or 35, I believe it is 56.7 please feel free to give me input i need help
molecules (mols) CO2 / molecules (mols) O2 = 1 from balanced eqn
78 g * 1 mol/44 g = 1. 772 mols of both CO2 and also O2
so how much mass is 1.772 mols of O2
1.772 mols * 32 g/mol = 56.7 grams of O2
To find the mass of oxygen present in the product, we first need to determine the number of moles of carbon dioxide produced.
Given:
Mass of CO2 = 78.0 g
Molar mass of CO2 = 44 g/mol
We can use the following formula to calculate moles:
Moles = Mass / Molar mass
Moles of CO2 = 78.0 g / 44 g/mol
Moles of CO2 = 1.77 mol
According to the balanced equation, the mole ratio between CO2 and O2 is 1:1. This means that for every 1 mole of CO2 produced, 1 mole of O2 is required.
Therefore, the number of moles of O2 present in the product is also 1.77 mol.
Now, we can calculate the mass of oxygen using the following formula:
Mass = Moles x Molar mass
Mass of O2 = 1.77 mol x 32 g/mol
Mass of O2 = 56.7 g
So, the mass of oxygen present in the product is 56.7 g. Hence, the correct answer is 56.7 g oxygen.
To determine the mass of oxygen present in the product, we need to use stoichiometry. Here's how we can approach this problem:
Step 1: Convert the mass of carbon dioxide (CO2) to the number of moles.
To do this, we use the molar mass of CO2, which is 44 g/mol.
m(CO2) = 78.0 g / (44 g/mol) = 1.77 mol
Step 2: Use the balanced equation to determine the mole ratio between CO2 and O2.
From the balanced equation: C + O2 → CO2
The mole ratio between CO2 and O2 is 1:1. This means that for every 1 mole of CO2 produced, 1 mole of O2 is consumed.
Step 3: Convert the number of moles of CO2 to the number of moles of O2.
Since the mole ratio is 1:1, the number of moles of O2 is also 1.77 mol.
Step 4: Convert the number of moles of O2 to the mass of O2.
To do this, we use the molar mass of O2, which is 32 g/mol.
m(O2) = 1.77 mol × (32 g/mol) = 56.64 g
Rounding to the correct number of significant figures, the mass of oxygen present in the product is approximately 56.7 g.
Therefore, the correct answer is 56.7 g oxygen.