You are a member of your local movie theater's club. Every time you see a movie at the theater, you earn 2 advantage points. When you earn 100 points, you get a free movie pass. Currently, you have 40 advantage points.
1. Write an equation to modle the number of movies m you have to watch before you earn a free movie pass.
2. Solve the equation. Show your work.
I need help writing the equation. I have this so far;
2m=100
m=50 (100÷2=50)
40÷2=20
50-20=30
40 + 2m = 100
Your equation shows how many movies will get you 100 points.
You did some more work and arrived at the correct answer, but you were asked to write an equation whose solution would provide the answer.
To write an equation that models the number of movies you have to watch before you earn a free movie pass, we can use the equation:
m = (100 - 40) / 2
In this equation:
- "m" represents the number of movies you have to watch.
- "100 - 40" represents the remaining points needed to reach 100 advantage points.
- "2" represents the number of advantage points earned per movie watched.
Now, let's solve the equation:
m = (100 - 40) / 2
m = 60 / 2
m = 30
Therefore, you would need to watch 30 more movies in order to earn a free movie pass.
To write the equation, let's define the number of movies you need to watch before earning a free movie pass as "m".
We know that every time you watch a movie, you earn 2 advantage points. So, the number of total advantage points you have after watching "m" movies would be 2m.
Since you earn a free movie pass after accumulating 100 points, we can set up the equation:
2m = 100
Now, let's solve the equation:
Divide both sides of the equation by 2 to isolate "m":
m = 100 / 2
Simplifying the right side:
m = 50
So, you need to watch 50 movies in order to earn a free movie pass.
To determine how many more movies you need to watch from your current advantage point of 40, you subtract your current advantage points (40) from the total advantage points required (100):
100 - 40 = 60
Therefore, you need to watch 60 more movies to earn a free movie pass.