Consider a basic solution diluted by a factor of 10. Calculate the pH of a 0.10 M solution of OH- and a 0.010 M solution of OH-. How did the pH change? Please help ASAP!!! :(
pH is the negative logarithm of the H+ concentration
pOH is the negative logarithm of the OH- concentration
pH + pOH = 14
0.10 M solution of OH- ... log(.1) = -1 ... pOH = 1 ... pH = 13
0.010 M solution of OH- ... log(.01) = -2 ... pOH = 2 ... pH = 12