write y=-0.5x+0.8 in standard form using integers
i think it would either be
-5x+10y=8
or
5x+10y=8
does "-0.5 x" change sign when it "crosses" the equal symbol?
no
so, you have
y=-0.5x+0.8
10y = -5x + 8
So, how do you get that 5x on the other side?
Ok standard for is Ax+By=c
We would multiply by ten
10y=-5x+8
Then we would add -5x to both sides of the equation to get x on the same side as y
-5x+10y=8
That’s your answer
To write the equation y=-0.5x+0.8 in standard form using integers, you need to eliminate the decimal and fraction coefficients.
Let's start by getting rid of the decimal coefficient by multiplying the entire equation by 10:
10y = -5x + 8
Now, we need to make the coefficients integers by eliminating the fractional coefficient. To do this, we can multiply every term in the equation by 2:
20y = -10x + 16
Lastly, let's rearrange the equation in standard form, where the x and y terms are on the same side, and the constant term is on the other side:
10x + 20y = 16
So, the equation y=-0.5x+0.8 in standard form using integers is 10x + 20y = 16.