The bearing of q from p is 250° and the bearing of r from p is 160° . If q is equidistant from p and r ,find the bearing of r and p
Did you make your sketch?
Clearly the angle at P is 90°
You then have pq = pr, that is, one leg is equal to the hypotenuse,
which of course is not possible.
The question is flawed, unless I misread it.
The bearing of q from p is 250 and the bearing from q is 160. If q is equidistant from p and r, find the bearing of r and p.
The bearing of Q from P is 250° and the bearing of R from Q is 160° .if Q is equidistant from P and R ,find the bearing of R from P.
Yes
To find the bearing of r from p, we can start by drawing a diagram.
1. Draw a point p as the starting point.
2. Draw a line segment from p to q with a bearing of 250°.
3. Draw another line segment from p to r with a bearing of 160°.
Since q is equidistant from p and r, we can draw a circle with center at q that passes through p and r.
4. Draw a circle centered at q that passes through both p and r.
Now, let's find the bearing of r from p:
5. Draw segment rq to complete the triangle pqr.
6. Using the triangle, find the angle at p.
a. Since p is the center of the circle, the angle at p is 180°.
b. Label this angle as ∠p.
7. Find the angle at r.
a. ∠prq is a linear angle with ∠p, so ∠prq = 180° - ∠p.
b. Label this angle as ∠r.
8. Find the bearing of r from p.
a. Since the bearing is measured clockwise from the north, we need to convert the bearing to the corresponding angle.
i. For example, a bearing of 250° is equivalent to an angle of 90° + 250° = 340°.
ii. Convert the bearing of q to an angle and label it as ∠q.
b. The bearing of r from p is the sum of the bearings ∠r and ∠q.
9. Calculate the bearing of r from p.
a. Adding the angles ∠r and ∠q will give the bearing of r from p.
Using this method, we can find the bearing of r from p.