A rectangular container measures 4m by 3m by 500cm. The container is completely filled with 0. 5m a long cubic packets. How many such packets are needed to filled 3/4 of the container?
convert 500cm to meters : 500cm = 0.5 m
volume of rectangular container:
v = length x width x height
v = 4 x 3 x 0.5
v = 6m^3
volume of cubic packets:
v = length x width x height
v = 0.5 x 0.5 x 0.5
v = 0.125 m^3
3/4 of rectangular container: 3/4 x 6 = 4.5 m^3
so 4.5 m^3 is 3/4 of the container
4.5 / 0.125 = 36 containers
therefore 36 containers fit in 3/4 of the container
I can't understand where 36 is coming from
To solve this problem, we need to convert all measurements to the same unit of measurement. Let's convert everything to meters since it is the most common unit.
Given:
Length of container = 4m
Width of container = 3m
Height of container = 500cm (which is 5m after conversion)
To find the volume of the container, we multiply the length, width, and height:
Volume of container = Length × Width × Height = 4m × 3m × 5m = 60 cubic meters
Now, we need to find how many cubic packets are needed to fill 3/4 (or 75%) of the container.
To calculate this, we multiply the volume of the container by 75%:
Volume filled = 60 cubic meters × 75% = 45 cubic meters
Since each cubic packet is 0.5m long, we divide the volume filled by the volume of each cubic packet to find the number of packets needed:
Number of cubic packets needed = Volume filled ÷ Volume of each cubic packet
Number of cubic packets needed = 45 cubic meters ÷ 0.5 cubic meters = 90 packets
Therefore, you would need 90 cubic packets to fill 3/4 of the given container.