Julie bought 3 toys. The first toy cost half of his money but more than $100. The second toy cost half of his money and more than $200 was leftover. Finally, the third toy cost him half of what was left over which was more than $300. How much money did he have in the beginning?
Let's solve the problem step by step:
Let's say Julie's starting amount of money is X.
According to the given information:
1. The first toy cost half of Julie's money but more than $100.
So, the cost of the first toy is X/2 and it is more than $100.
2. The second toy cost half of Julie's money and more than $200 was leftover.
After buying the first toy, Julie has (X - X/2) = X/2 amount of money left.
So, the cost of the second toy is X/2, and (X/2 - X/2) = 0. Since more than $200 was leftover, this implies that X/2 > $200.
3. The third toy cost Julie half of what was left over, which was more than $300.
After buying the second toy, Julie has no money left.
So, the cost of the third toy is 0, and (0 - X/2) < $300. But this is contradictory since it should be more than $300.
Therefore, the problem seems to have no valid solution according to the given information.
Please double-check the information provided or provide additional details if available.