what volume of oxygen gas measures at s.t.p will be produced from the decomposition of 2.50g of potasium trioxochlorate (v) (K =39,Cl =35.5, O =16 molar volume of a gas at s.t.p =22.4dm-3
Note that your name for KClO3 is not approved by IUPAC.
2KClO3 ==> 2KCl + 3O2
mols KClO3 = grams/molar mass = 2.50/122.5 = ?
mols O2 = mols KClO3 x (3/2) = ? Then are 22.4 L/mole O2 produced at STP.
Post your work if you get stuck.
To find the volume of oxygen gas produced, we need to first calculate the number of moles of potassium trioxochlorate (V) (KClO3), and then use stoichiometry to find the number of moles of oxygen gas generated. Finally, we can convert the moles of oxygen gas to volume using the molar volume of a gas at STP.
1. Calculate the molar mass of potassium trioxochlorate (V):
- K: 1 * 39 = 39 g/mol
- Cl: 1 * 35.5 = 35.5 g/mol
- O: 3 * 16 = 48 g/mol
Total molar mass = 39 + 35.5 + 48 = 122.5 g/mol
2. Calculate the number of moles of potassium trioxochlorate (V):
- Given mass of KClO3 = 2.50 g.
- Number of moles = given mass / molar mass
- Number of moles = 2.50 g / 122.5 g/mol
3. Use the balanced chemical equation to find the moles of oxygen produced:
- The balanced equation for the decomposition of potassium trioxochlorate (V) is:
2KClO3(s) -> 2KCl(s) + 3O2(g)
- From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
- So, moles of O2 = (moles of KClO3) * (3/2)
4. Convert the moles of oxygen gas to volume:
- Given molar volume of a gas at STP = 22.4 dm^3/mol
- Volume of O2 = moles of O2 * molar volume
Putting it all together:
1. Calculate moles of KClO3:
Moles of KClO3 = 2.50 g / 122.5 g/mol
2. Calculate moles of O2:
Moles of O2 = (moles of KClO3) * (3/2)
3. Calculate volume of O2:
Volume of O2 = (moles of O2) * (22.4 dm^3/mol)
Note: Make sure to use the proper units throughout the calculations to obtain the correct answer.