An apple drops from a tree and hits the ground in 1.5 secs. What is it’s speed just before it hits the ground?
KE final=PE initial
1/2 mv^2=mgh
v=sqrt(2gh)
Putang ina d ako nakakaintinde hahahaha
To calculate the speed of the apple just before it hits the ground, you need to know the distance it traveled and the time it took to fall.
The formula to calculate speed is:
Speed = Distance / Time
First, we need to calculate the distance the apple fell. We'll use the formula for free fall distance:
Distance = 1/2 * g * t^2
Where:
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time in seconds (1.5 seconds in this case)
Plugging in the values, we get:
Distance = 1/2 * 9.8 m/s^2 * (1.5 s)^2
Distance = 1/2 * 9.8 m/s^2 * 2.25 s^2
Distance = 10.125 m (rounded to three decimal places)
Now that we have the distance, we can calculate the speed using the formula:
Speed = Distance / Time
Speed = 10.125 m / 1.5 s
Speed ≈ 6.750 m/s
Therefore, the apple's speed just before it hits the ground is approximately 6.750 m/s.