acar accidently rolls off a cliff as it leaves the cliff it has a horizontal velocity of 13m/s it hits the ground at 60m from the shoreline work out
What does ejaje mean? Physics?
time taken = 60/13 seconds
if you want to find the height of the cliff, use that for t in
s = 1/2 at^2
To solve this problem, we need to break it down into two parts: the horizontal motion and the vertical motion of the car.
First, let's focus on the horizontal motion. We are given the horizontal velocity (Vx) of the car as it leaves the cliff, which is 13 m/s. Since there are no horizontal forces acting on the car, its horizontal velocity will remain constant throughout the motion.
The horizontal distance traveled by the car (d) is given as 60 m from the shoreline. Therefore, we can use the equation:
d = Vx * t
where:
- d is the horizontal distance traveled (60 m),
- Vx is the horizontal velocity (13 m/s), and
- t is the time.
Rearranging the equation to solve for time (t):
t = d / Vx
t = 60 m / 13 m/s
t ≈ 4.62 s (rounded to two decimal places)
Now, let's move on to the vertical motion of the car. We know that the car rolls off the cliff with an initial vertical velocity (Vy) of 0 m/s. The only vertical force acting on the car is gravity, causing it to accelerate downward. We can use the kinematic equation:
d = Vit + (1/2)at^2
where:
- d is the vertical distance traveled,
- Vi is the initial vertical velocity (0 m/s),
- a is the acceleration due to gravity (-9.8 m/s²), and
- t is the time.
As the car falls downward, the vertical distance traveled (d) can be calculated using the equation:
d = Vit + (1/2)at^2
d = 0 m/s * t + (1/2)(-9.8 m/s²)t^2
d = -4.9 t^2
Since the car hits the ground, the vertical distance traveled (d) is the height of the cliff, which we'll denote as h. Therefore:
h = -4.9 t^2
Substituting the calculated value of time (t) into the equation:
h = -4.9 * (4.62 s)^2
h ≈ -107.67 m (rounded to two decimal places)
Now, since the height of a cliff cannot be negative, we can take the absolute value of the calculated height to get the positive value of the cliff's height:
Cliff's height ≈ | -107.67 m | ≈ 107.67 m
Therefore, the height of the cliff from which the car rolled off is approximately 107.67 meters.