e^(−5−2x) = 5
once again
e^(−5−2x) = 5
is
ln e^(−5−2x) = ln 5
or
−5−2x = ln 5
all you need to know for all of this is:
anything^0 = 1
ln e^(the anything) = that same anything
e^(−5−2x) = 5
is
ln e^(−5−2x) = ln 5
or
−5−2x = ln 5
anything^0 = 1
ln e^(the anything) = that same anything