If N is the set of natural numbers that are factors of 24, choose the selection below that correctly shows this set in roster form.
a. {2 ,4, 6, 12}
b. {2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24}
c. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24}
d. {1, 2, 3, 4, 6, 8, 12, 24}
well 24 = 1*24 of course
24 = 2*12 = 2*3*4 = 2*2*2*3
2 2 2 3
2 2 6
2 4 3
2 12
3 8
so I have 1 2 3 4 6 8 12 24
thanks Damon!!!!
You are welcome.
To find the set of natural numbers that are factors of 24, we need to list all the numbers that divide evenly into 24 without leaving a remainder.
We can start by listing the numbers from 1 to 24 and checking if each number divides 24 evenly.
1 ÷ 24 = 24 (remainder 0)
2 ÷ 24 = 12 (remainder 0)
3 ÷ 24 = 8 (remainder 0)
4 ÷ 24 = 6 (remainder 0)
5 ÷ 24 = 4 (remainder 4)
6 ÷ 24 = 4 (remainder 0)
7 ÷ 24 = 3 (remainder 3)
8 ÷ 24 = 3 (remainder 0)
9 ÷ 24 = 2 (remainder 2)
10 ÷ 24 = 2 (remainder 0)
11 ÷ 24 = 2 (remainder 2)
12 ÷ 24 = 2 (remainder 0)
13 ÷ 24 = 1 (remainder 13)
14 ÷ 24 = 1 (remainder 14)
15 ÷ 24 = 1 (remainder 15)
16 ÷ 24 = 1 (remainder 16)
17 ÷ 24 = 0 (remainder 17)
18 ÷ 24 = 0 (remainder 18)
19 ÷ 24 = 0 (remainder 19)
20 ÷ 24 = 0 (remainder 20)
21 ÷ 24 = 0 (remainder 21)
22 ÷ 24 = 0 (remainder 22)
23 ÷ 24 = 0 (remainder 23)
24 ÷ 24 = 1 (remainder 0)
From this list, we can see that the numbers 1, 2, 3, 4, 6, 8, 12, and 24 divide evenly into 24 without leaving a remainder. Therefore, the set of natural numbers that are factors of 24 in roster form is {1, 2, 3, 4, 6, 8, 12, 24}.
So, the correct option is d. {1, 2, 3, 4, 6, 8, 12, 24}.