Halima runs a circular of 500m length find distance and displacement
Very incomplete.
If all the way around the circle then displacement vector is ZERO (vector from start to finish has zero length)
distance is 500
To find the distance and displacement, we need to understand the definitions of these terms.
Distance: Distance is the length of the actual path traveled by an object. It is a scalar quantity, meaning it has magnitude but no direction. It is always positive and cannot be negative.
Displacement: Displacement is the shortest length between the initial and final position of an object, taking into account direction. It is a vector quantity, meaning it has both magnitude and direction. It can be positive, negative, or zero.
Now, let's calculate the distance and displacement for Halima's circular run of 500m.
1. Distance: Since Halima runs a circular path, we can find the distance by calculating the circumference of the circle. The formula for calculating the circumference of a circle is C = 2πr, where r is the radius.
C = 2π * r
In this case, we know the length of the circular path is 500m. The circumference is equal to the distance traveled by Halima.
500 = 2π * r
To find the radius, we can rearrange the formula:
r = 500 / (2π)
Now, we can calculate the radius using a calculator:
r ≈ 79.6m
Using the radius, we can calculate the distance:
Distance = Circumference = 2π * r
Distance ≈ 2π * 79.6
Distance ≈ 500.96m
Therefore, the distance traveled by Halima is approximately 500.96m.
2. Displacement: Displacement considers the shortest distance between the initial and final positions, so for a circular path, the displacement is zero. This is because the starting and ending points are the same, and the shortest distance between them is zero.
Therefore, the displacement is 0m.
In summary:
- The distance traveled by Halima is approximately 500.96m.
- The displacement of Halima is 0m.