Triose phosphate isomerase has a rate enhancement of 1.0x109. If the enzyme-catalyzed rate is 1500 nmol s-1, what would the reaction rate be without the enzyme? Convert your answer to nmol day-1 before entering. (Pay very close attention to units.)
Well, well, well, triose phosphate isomerase, making its grand entrance into our conversation! Now, let me put on my funny hat and help you out with your question.
So, triose phosphate isomerase is a snazzy enzyme that has a rate enhancement of 1.0x10^9. Impressive, right? Now, if the enzyme-catalyzed rate with triose phosphate isomerase is 1500 nmol s^-1, we want to know what the reaction rate would be without this jazzy enzyme.
To convert this into nmol day^-1, we'll have to do a little dance with the units. Are you ready? Here we go!
1 day has 24 hours, and 1 hour has 60 minutes, and 1 minute has 60 seconds. So, 1 day has 24 x 60 x 60 = 86400 seconds. Phew, that was a workout!
Now, let's boogie with the numbers:
1.0 x 10^9 (rate enhancement) x 1500 (enzyme-catalyzed rate) / 86400 (seconds in a day) = 17361.11 nmol day^-1
Voila! The reaction rate without triose phosphate isomerase would be approximately 17361.11 nmol day^-1. Hope this helps you calculate the enzyme-less dance moves of triose phosphate!
To find the reaction rate without the enzyme, we can divide the enzyme-catalyzed rate by the rate enhancement.
Reaction rate without the enzyme = Enzyme-catalyzed rate / rate enhancement
Given:
Enzyme-catalyzed rate = 1500 nmol s^-1
Rate enhancement = 1.0x10^9
Plugging in the values:
Reaction rate without the enzyme = 1500 nmol s^-1 / (1.0x10^9)
Now, we need to convert the rate from s^-1 to day^-1.
1 day has 24 hours, and 1 hour has 60 minutes, and 1 minute has 60 seconds.
Therefore, 1 day = 24 hours/day * 60 minutes/hour * 60 seconds/minute = 86,400 seconds/day
To convert from s^-1 to day^-1, we need to divide by the number of seconds in a day:
Reaction rate without the enzyme = (1500 nmol s^-1 / (1.0x10^9)) * (1 day / 86,400 seconds)
Calculating the answer:
Reaction rate without the enzyme = (1500 nmol / 1.0x10^9) * (1 day / 86,400 seconds)
= 1.74 nmol day^-1
To find the reaction rate without the enzyme, we can use the rate enhancement and the enzyme-catalyzed rate.
First, let's convert the enzyme-catalyzed rate from seconds to days. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute. So, the conversion factor from seconds to days is:
1 day = 24 hours * 60 minutes * 60 seconds
To convert nmol s^-1 to nmol day^-1, we need to multiply the enzyme-catalyzed rate by the conversion factor:
1500 nmol s^-1 * (24 hours * 60 minutes * 60 seconds) = 1500 nmol * (24 * 60 * 60) day^-1
Next, let's calculate the reaction rate without the enzyme using the rate enhancement. The rate enhancement tells us how much faster the reaction occurs with the enzyme compared to without the enzyme.
The reaction rate without the enzyme is equal to the enzyme-catalyzed rate divided by the rate enhancement:
Reaction rate without enzyme = enzyme-catalyzed rate / rate enhancement
Plugging in the given values:
Reaction rate without enzyme = 1500 nmol * (24 * 60 * 60) day^-1 / 1.0x10^9
Let's calculate this value now.