The perimeter of an isosceles triangle is 28 one of is sides is (6y-2x +1),another is 4y then the base is x+2y.find x and y hence state the lengths of the sides of the triangle

If x+ 2y is the base , then 6y - 2x +1 = 4y

2y - 2x = -1
and x+2y + 4y + 6y -2x + 1= 28
12y - x = 27 or x = 12y - 27
Use substitution to find x and y

To find the lengths of the sides of the triangle, we need to use the given information about the perimeter and the sides:

1. Perimeter of the triangle: 28

2. One of the sides: 6y - 2x + 1

3. Another side: 4y

4. Base: x + 2y

We can set up an equation using the given information:

Perimeter = Side 1 + Side 2 + Base

28 = (6y - 2x + 1) + 4y + (x + 2y)

Simplifying the right side of the equation:

28 = 6y - 2x + 1 + 4y + x + 2y

Combine like terms:

28 = 12y - x + 1 + x + 2y

Combine like terms:

28 = 14y + 1

Subtract 1 from both sides:

27 = 14y

Divide both sides by 14:

y = 27/14

Thus, y is equal to 27/14.

Next, we can substitute the value of y back into the equation to find x.

28 = (6y - 2x + 1) + 4y + (x + 2y)

Replacing y with 27/14:

28 = (6(27/14) - 2x + 1) + 4(27/14) + (x + 2(27/14))

Simplifying:

28 = (27/7 - 2x + 1) + (54/14 + x + 27/7)

28 = (27/7 - 2x + 1) + (27/7 + x + 27/7)

Combine like terms:

28 = (54/7 - 2x) + (54/7 + x)

28 = (54 - 14x)/7 + (54 + 7x)/7

Combine the fractions:

28 = (108 - 14x + 54 + 7x)/7

Multiply both sides by 7 to remove the denominator:

196 = 108 - 14x + 54 + 7x

Combine like terms:

196 = 162 - 7x

Subtract 162 from both sides:

34 = -7x

Divide both sides by -7:

x = -34/-7

x = 34/7

Thus, x is equal to 34/7.

Now that we have found the values of x and y, we can substitute them back into the expressions for the sides to find their lengths:

Side 1: 6y - 2x + 1
Substituting y = 27/14 and x = 34/7:

Side 1 = 6(27/14) - 2(34/7) + 1
= 81/7 - 68/7 + 1
= 14/7
= 2

Side 2: 4y
Substituting y = 27/14:

Side 2 = 4(27/14)
= 27/7
= 3

Base: x + 2y
Substituting x = 34/7 and y = 27/14:

Base = (34/7) + 2(27/14)
= 34/7 + 27/7
= 61/7

Therefore, the lengths of the sides of the triangle are:
Side 1: 2
Side 2: 3
Base: 61/7