A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 29.8 m/s. At the same time, it has a horizontal velocity of 56.7 m/s.
At what speed does the vehicle move along its descent path?
Answer in units of m/s.
At what angle with the vertical is its path? Answer in units of ◦.
I got 64.05 for the first part?
v^2 = 29.8^2 + 56.7^2 = 888 + 3215 = 4103
v = sqrt (4103) = 64.05 right
yay!! but I have no idea how to answer the second part...
tan angle above straight down = 29.8/56.7
= .5256
so angle above straight down = 27.7 degrees
angle below straight up = 180 - 27.7 = 152.3 if that is what they mean by angle to vertical.
I also tried 152.3 and it tells me its wrong. Im so sorry for troubling you so much. Thank you, I really appreciate it.
Whoops,did that tangent backwards
angle below horizontal = 27.7
so angle above straight down = 90 - 27.7 = 62.3 degrees above vertical down