A pair of 328.1 N vectors are perpendicular. What is the magnitude of their resultant? Answer in units of N.
diagonal of square :)
1^2 +1^2 = 2
so
328.1 sqrt 2 Newtons
Thats also what I got originally but its incorrect :(
Then something is cockeyed in the problem statement or in the answer choices.
What should I submit as an answer? 2?
328.1 sqrt 2 = 464.0 N
they want 4 significant figures so write it that way.
Fr = sqrt(328.1^2+328.1^2) = 464 N.
That is all I can think of.
Thank you so much Damon for your help!!! :)
You are welcome.
To find the magnitude of the resultant vector, we can use the Pythagorean theorem, since the given vectors are perpendicular to each other.
Let's call the two given vectors A and B.
According to the Pythagorean theorem, the magnitude of the resultant vector (R) can be found using the formula:
|R| = sqrt(|A|^2 + |B|^2)
Here, |A| represents the magnitude of vector A, and |B| represents the magnitude of vector B.
Given that both vectors have a magnitude of 328.1 N, we can substitute this value into the formula:
|R| = sqrt((328.1)^2 + (328.1)^2)
Simplifying the equation:
|R| = sqrt(2 * (328.1)^2)
|R| = sqrt(2 * 107651.61)
|R| = sqrt(215303.22)
|R| ≈ 464.33 N
Therefore, the magnitude of the resultant vector is approximately 464.33 N.