3 raise to the power of 4x-1=8 show workings.
I can see this working if you meant:
3^(4x) - 1 = 8
3^(4x) = 9
3^(4x) = 3^2
can you predict my next step ?
3raise to the power of 4x-1=8 is therefore equal to 3raise to the power of 3x =2 raise to the power of 3, 3 raise to the power of x =2 log3 raise to the power of 2=x
What is the anwer to the question
To solve the equation 3^(4x-1) = 8, we need to isolate the variable x.
Step 1: Rewrite 8 as a power of 3. Since 8 = 2^3, we can write it as 3^3.
Step 2: Set the exponents equal to each other. We have 3^(4x-1) = 3^3.
Step 3: Since the bases are the same (both are 3), we can set the exponents equal to each other: 4x - 1 = 3.
Step 4: Solve for x. Add 1 to both sides of the equation: 4x = 4.
Step 5: Divide both sides by 4: x = 1.
So, the solution to the equation 3^(4x-1) = 8 is x = 1.