Write an equation of a line which is passing through the point (8, −6) and is parallel to another line, whose slope is −2
(8, -6), m = -2.
Y = mx + b.
m = -2.
b = y-mx = -6 - (-2*8) = 10.
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To find the equation of a line parallel to another line, we need to know its slope. In this case, we are given that the slope of the other line is -2. Since parallel lines have the same slope, the slope of our line will also be -2.
The equation of a line can be written in slope-intercept form as y = mx + b, where m is the slope and b is the y-intercept. We already know the slope, -2, and we need to find the y-intercept.
To find the y-intercept, we can use the point (8, -6) that the line passes through. We substitute the x and y values into the equation and solve for b.
-6 = -2 * 8 + b
-6 = -16 + b
b = -6 + 16
b = 10
Now we have the slope, m = -2, and the y-intercept, b = 10. The equation of the line parallel to the line with slope -2 and passing through the point (8, -6) is:
y = -2x + 10
use the point-slope form:
y+6 = -2(x-8)