Two forces are applied to a car in an effort to move it, as shown in the following figure, where F1 = 453 N and F2 = 400 N. (Assume up and to the right as positive directions.)(F1 is 8degrees and F2 is 35degreed)
(a) What is the resultant of these two forces?
magnitude
direction
(b) If the car has a mass of 3805 kg, what acceleration does it have? Ignore friction.
Really need help
To solve this problem, we can break down the forces into their respective components and then find the resultant force by adding the components together.
(a) Finding the resultant force:
First, let's find the horizontal and vertical components of each force.
For F1 = 453 N at 8 degrees:
Horizontal component (F1x) = F1 * cos(8 degrees)
Vertical component (F1y) = F1 * sin(8 degrees)
For F2 = 400 N at 35 degrees:
Horizontal component (F2x) = F2 * cos(35 degrees)
Vertical component (F2y) = F2 * sin(35 degrees)
Now, let's add the horizontal and vertical components together to find the resultant components:
Resultant horizontal component (Rx) = F1x + F2x
Resultant vertical component (Ry) = F1y + F2y
To find the magnitude of the resultant force, we can use the Pythagorean theorem:
Resultant magnitude (R) = sqrt(Rx^2 + Ry^2)
To find the direction of the resultant force, we can use the inverse tangent function:
Resultant direction (θ) = atan(Ry / Rx)
By substituting the values into the above formulas, we can find the answers.
(b) Finding the acceleration of the car:
Since we know the resultant force acting on the car, we can use Newton's second law, F = ma, to find the acceleration.
a = F / m
By substituting the values of the resultant force (R) and the mass of the car (m) into the formula, we can find the acceleration of the car.
Now that you have the general approach to solving the problem, you can plug in the given values and do the calculations to find the answers. Good luck!
I did this a few minutes ago
https://www.jiskha.com/questions/1805564/Two-forces-are-applied-to-a-car-in-an-effort-to-move-it-as-shown-in-the-following