A cheetah can run at a maximum speed
96.6 km/h and a gazelle can run at a maximum speed of 78.5 km/h.
If both animals are running at full speed,
with the gazelle 93.9 m ahead, how long before
the cheetah catches its prey?
Answer in units of s.
Vc = 96.6km/h = 96,600m/3600s = 26.8 m/s.
Vg = 78.5km/ = 78,5 00m/3600s = 21.8 m/s.
Dc = Dg.
26.8*T = 93.9 + 21.8*T.
T =
where does 3600 come from?
3600 comes from the conversion from hour to seconds, there are 3600 seconds in an hour.
To find the time it takes for the cheetah to catch the gazelle, we can use the formula:
Time = Distance / Speed
First, we need to convert the distance from meters to kilometers, since the speeds are given in kilometers per hour. There are 1000 meters in a kilometer, so the distance of 93.9 meters converts to 0.0939 kilometers.
Now, let's find the time it takes for each animal to reach the given distance.
For the cheetah:
Time taken by the cheetah = Distance / Speed
Time taken by the cheetah = 0.0939 km / 96.6 km/h
For the gazelle:
Time taken by the gazelle = Distance / Speed
Time taken by the gazelle = 0.0939 km / 78.5 km/h
Calculating these values gives us:
Time taken by the cheetah = 0.000971 h
Time taken by the gazelle = 0.001196 h
Now, let's convert the time taken to seconds. There are 60 minutes in an hour and 60 seconds in a minute, so:
Time taken by the cheetah (in seconds) = 0.000971 h * 60 min/h * 60 s/min
Time taken by the gazelle (in seconds) = 0.001196 h * 60 min/h * 60 s/min
Calculating these values gives us:
Time taken by the cheetah = 3.49 s (rounded to two decimal places)
Time taken by the gazelle = 4.43 s (rounded to two decimal places)
Therefore, it will take approximately 3.49 seconds for the cheetah to catch the gazelle.