Dr. Pepper left Oakville at 9:00 AM and drove to Central City at 60 km/h. H. Salt left Oakville at 11:00 AM and traveled the same route to Central City. If both men arrived at Central City by 4:00 PM at what rate did H Salt travel. We have to set the questions up as d=rt and im not sure how I would set it up. Would I do 7(x)=5(x-2)?
Not quite. x and x-2 are the time needed. You already have that. You want the speed. So,
7*60 = 5x
You have multiplied time * time, rather than time * speed.
No
First of all you have to define what x is.
let x be the speed of H Salt
they went the same distance, which we can find
Pepper went 7 hrs at 60 km/h , so the distance is 420 km
Salt did the same trip in 5 hours
so 5x = 420
x = 84
So H Salt went at 84 km/h
your equation would solve to
7x = 5x - 10
2x = -10
x = -5
clearly a meaningless result.
What was that equation supposed to say?
To find the rate at which H. Salt traveled, we can set up an equation using the distance, rate, and time formula: d = rt.
Let's first find the time it took for Dr. Pepper to travel from Oakville to Central City. He left at 9:00 AM and arrived by 4:00 PM, which means he traveled for a total of 7 hours (since there are 7 hours between 9:00 AM and 4:00 PM).
Now let's set up an equation for Dr. Pepper's distance using d = rt. We know the rate (60 km/h) and the time he traveled (7 hours):
d1 = 60 km/h * 7 hours
d1 = 420 km (distance traveled by Dr. Pepper)
Next, let's consider H. Salt's travel time. He left Oakville at 11:00 AM and arrived by 4:00 PM, which means he traveled for a total of 5 hours (since there are 5 hours between 11:00 AM and 4:00 PM).
Now, let's set up an equation for H. Salt's distance, using the same rate (which we want to find) and his travel time:
d2 = r * 5 hours
Since both Dr. Pepper and H. Salt traveled the same route from Oakville to Central City, their distances should be the same:
d1 = d2
420 km = r * 5 hours
Now we can solve for the rate (r):
r = 420 km / 5 hours
r = 84 km/h
Therefore, H. Salt traveled at a rate of 84 km/h.