Consider the points
A
(
1
,
1
)
A(1, 1)
,
B
(
2
,
4
)
B(2, 4)
,
C
(
3
,
−
1
)
C(3, -1)
, and
D
(
5
,
6
)
D(5, 6)
. Point A is joined to point B to create segment AB and point C is joined to point D to create segment CD.
Please type your post in normal form. I cannot read it as is.
I read that as:
Consider the points
A(1,1), B(2,4),C(3,-1), and D(5,6). Point A is joined to point B to create segment AB and point C is joined to point D to create segment CD.
Done.
Is there some kind of a question here ?
Maybe showing them to be parallel or comparison between lengths ?
Okay, you have mentioned four points - A(1, 1), B(2, 4), C(3, -1), and D(5, 6). You want to create segments AB and CD.
To find the equation of a straight line passing through two points, we can use the point-slope form of the equation of a line: y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is one of the given points on the line.
First, let's find the equation of line AB:
Step 1: Calculate the slope (m) using the formula m = (y2 - y1) / (x2 - x1):
m = (4 - 1) / (2 - 1) = 3 / 1 = 3
Step 2: Choose one of the given points, let's say A(1, 1). Substitute the values of (x1, y1) and m into the point-slope form:
y - 1 = 3(x - 1)
Simplifying the equation will give us the equation of line AB.
Similarly, we can find the equation of line CD:
Step 1: Calculate the slope (m) using the formula m = (y2 - y1) / (x2 - x1):
m = (6 - (-1)) / (5 - 3) = 7 / 2 = 3.5
Step 2: Choose one of the given points, let's say C(3, -1). Substitute the values of (x1, y1) and m into the point-slope form:
y - (-1) = 3.5(x - 3)
Simplifying the equation will give us the equation of line CD.
Let's solve these equations to find the equations of the lines AB and CD.