You have a population where the percentage of homozygous dominant individuals is 27%. Use the equation to fill this table.
What table? What equation?
Cannot copy and paste here.
To fill the table, we need to know the equation you are referring to. Please provide the equation so that I can assist you further.
I assume you are referring to the Hardy-Weinberg equation, which states that in a population in genetic equilibrium, the frequencies of alleles and genotypes will remain constant from generation to generation.
The equation is:
p^2 + 2pq + q^2 = 1
Where:
p = frequency of the dominant allele
q = frequency of the recessive allele
p^2 = frequency of homozygous dominant individuals
2pq = frequency of heterozygous individuals
q^2 = frequency of homozygous recessive individuals
Given that the percentage of homozygous dominant individuals is 27%, we can say p^2 = 0.27.
Now, let's fill in the table using the equation:
| p | q | p^2 | 2pq | q^2
-----------------------------------------------------------------------------
Allele | | | | |
Genotype| | | | |
To find the allele frequencies, we can take the square root of p^2 to get p:
p = sqrt(0.27) = 0.5196 (approximately)
The sum of both allele frequencies is 1, so we can find q:
q = 1 - p = 1 - 0.5196 = 0.4804 (approximately)
Now let's calculate the remaining values:
p^2 = 0.27
2pq = 2 * 0.5196 * 0.4804 = 0.499 (approximately)
q^2 = (0.4804)^2 = 0.2311 (approximately)
Now we can complete the table:
| p | q | p^2 | 2pq | q^2
-----------------------------------------------------------------------------
Allele | 0.5196 | 0.4804 | | |
Genotype| | | 0.27 | 0.499 | 0.2311
Please note that the values in the table are rounded for simplicity and may not exactly add up to 1 due to rounding errors.