Bob's uncle is four times as old as Bob is now. In twelve years Bob's age will be one half of his uncles age . How old are they now?
in algebra, they have told you that
u = 4b
b+12 = 1/2 (u+12)
Now just solve
Bob is X years old.
Bob's uncle is 4x years old.
12 years later:
x+12 = (4x+12)/2.
2x+24 = 4x+12,
X =
4x =
To solve this problem, let's represent Bob's current age as x.
According to the problem, Bob's uncle is four times as old as Bob is now, so his age can be represented as 4x.
In twelve years, Bob's age will be x + 12, and his uncle's age will be 4x + 12.
The problem states that Bob's age in twelve years will be one half of his uncle's age, so we can form the following equation:
x + 12 = 1/2 * (4x + 12)
Now, let's solve the equation:
Multiply both sides by 2 to remove the fraction:
2(x + 12) = 4x + 12
Simplify:
2x + 24 = 4x + 12
Subtract 2x from both sides:
24 = 2x + 12
Subtract 12 from both sides:
12 = 2x
Divide both sides by 2:
6 = x
So, Bob's current age is 6 years old.
Substitute this value back into the equation to find the uncle's age:
Uncle's age = 4x = 4 * 6 = 24
Therefore, Bob is currently 6 years old, and his uncle is 24 years old.